6X-9Y+3Z
----------
3
WOULD I BE CORRECT IN THINKING THAT WOULD BE 2X-3Y+Z?
THANKS!
You are right. But here are the steps which you
must follow in case in the future you have a more
complicated but similar problem, where the
denominator does not divide exactly into all the
numerator terms, as it does in this one:
6X - 9Y + 3Z
——————————————
3
There are three terms in the top, so start out
with a row of three lines and signs, the same
signs that are between the terms:
———— - ———— + ————
Then write in the three numerators on top of the
lines:
6X 9Y 3Z
———— - ———— + ————
and then write the common denominator under each
line:
6X 9Y 3Z
———— - ———— + ————
3 3 3
Now cancel each of the 3's into the numerators:
2 3 1
6X 9Y 3Z
———— - ———— + ————
3 3 3
1 1 1
2X 3Y Z
———— - ———— + ———
1 1 1
or just
2X - 3Y + Z
This one was easy and so you could just have
done it in your head, but the more complicated
ones must be done the above way.
Edwin
^
/9|o\
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