Hi,
Note; vertex form of a Parabola opening up(a>0) or down(a<0),
whereis the vertex and
is the Line of Symmetry
f(x)=1/5 (x+5)^(2)+6 || V(-5,6) 1/5> 0, parabola opens Up, vertex in a min point
The line of symmetry is? x = -5
the minimum value of f(x) is 6
the value, f(-5) = 6, is a minimum