SOLUTION: The sum of 2 numbers is 11. The cube of their sum exceeds the sum of their cubes by 792. Find the numbers. So far, I've got x+y=11 and x^3+y^3+792=11^3. I've tried using substituti

Algebra ->  Systems-of-equations -> SOLUTION: The sum of 2 numbers is 11. The cube of their sum exceeds the sum of their cubes by 792. Find the numbers. So far, I've got x+y=11 and x^3+y^3+792=11^3. I've tried using substituti      Log On


   

Question 608413: The sum of 2 numbers is 11. The cube of their sum exceeds the sum of their cubes by 792. Find the numbers. So far, I've got x+y=11 and x^3+y^3+792=11^3. I've tried using substitution, but the answer didn't exactly make any sense. I greatly appreciate the help.
Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
y3,x=-27
& y=8,x=-27