SOLUTION: write equation of line containing point (-2,4) and perpendicular to line 5x+2y=3
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Question 590896: write equation of line containing point (-2,4) and perpendicular to line 5x+2y=3
Answer by ad_alta(240) (Show Source): You can put this solution on YOUR website!
In order to be perpendicular to the given line, the slope of our line must be the negative reciprocal of the given line. Thus, our slope should be 2/5. So far we have: y=(2/5)x+b. Plugging in the point to solve for 'b,' 4=(2/5)(-2)+b, so b=24/5 and our line is y=(2/5)*x+24/5.