SOLUTION: The square of y varies inversely as x and directly as z. If y = 3 when x = 12 and z = 21, find y when x = 8 and z = 28.
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Question 586261: The square of y varies inversely as x and directly as z. If y = 3 when x = 12 and z = 21, find y when x = 8 and z = 28.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
x * y^2 = k * z
12 * 3^2 = k * 21 ___ (12 * 9) / 21 = k ___ 36/7 = k
8 * y^2 = (36/7) * 28
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