SOLUTION: I am having trouble solving a system of equations: {{{4sqrt(x^2-3x) - 3sqrt(y^2+6y)= -4}}} {{{sqrt(x^2-3x) + sqrt(y^2+6y)= 6}}} I squared both sides to remove the radical:

Question 573236: I am having trouble solving a system of equations:

I squared both sides to remove the radical:

and that is as far as I've gotten.
thanks
lpkitty
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!

But these are like terms so let's simplify things by using elimination
Multipl the 2nd equation by 3, add to the 1st equation

-----------------------------------adding eliminates the y radical, so we have

divide both sides by 7

square both sides
x^2 - 3x = 4
x^2 - 3x - 4 = 0
Factors to
(x-4)(x+1) = 0
two solutions
x = -1
x = 4
:
Use the 2nd original equation to find y

square both sides
y^2 + 6y = 16
y^2 + 6y - 16 = 0
Factors to
(y+8)(y-2) = 0
Y = -8
Y = 2
:
You should check all the solutions in the original equations

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