# SOLUTION: The equations of two lines are given as x + 3y = 0 and 2x - y= -7. What are the coordinates of the point of intersection. How do I solve this Thank you, Natasha

Algebra ->  Algebra  -> Systems-of-equations -> SOLUTION: The equations of two lines are given as x + 3y = 0 and 2x - y= -7. What are the coordinates of the point of intersection. How do I solve this Thank you, Natasha      Log On

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 Algebra: Systems of equations that are not linear Solvers Lessons Answers archive Quiz In Depth

 Question 549455: The equations of two lines are given as x + 3y = 0 and 2x - y= -7. What are the coordinates of the point of intersection. How do I solve this Thank you, NatashaAnswer by TutorDelphia(193)   (Show Source): You can put this solution on YOUR website!Hi Natasha, Finding x and y and writing them as an ordered pair (x,y) is what your teacher is looking for here. With systems of equations there are three ways to solve it, graphing, substitution or elimination. I'll show you elimination and graphing. x + 3y = 0 and 2x - y= -7 Lets multiply both sides of the second equation by 3 6x-3y=-21 Now lets add the two equations 6x-3y=-21 x + 3y = 0 7x=-21 x=-3 We can then plug in -3 for x to find y 2*(-3)-y=-7 y=1 so your answer is (-3,1) To graph we have to have the equations in slope intercept form x + 3y = 0 3y=-x y=-x/3 2x - y= -7 -y=-2x-7 y=2x+7 and we see they intersect at (-3,1)