SOLUTION: I need to know how to graph 2x-7y=3 5x-4y=-6 And I also need to know how many solutions it has. Could you please help me? thanks!

Algebra.Com
Question 5472: I need to know how to graph
2x-7y=3
5x-4y=-6
And I also need to know how many solutions it has.
Could you please help me? thanks!

Answer by Abbey(339)   (Show Source): You can put this solution on YOUR website!
the easiest way is to set it up in slope intercept form (y=mx+b)and then plug in values for x to get a y - you then have a point to graph:
2x-7y=3
subtract 2x from both sides of the equation
-7y=-2x+3
Divide both sides by -7

The slope to the graph is and it crosses the y axis at (0,3/7)
by putting in 1 for x, we get another point (1,5/7) Draw a line that crosses both of these points.
Do the same to the other equation
5x-4y=-6
subtract 5x from both sides:
-4y=-5x-6
divide both sides by -4

we have the point (0,6/4), get a second point by substituting 1 for x.. (1,11/4) draw a line that extends through these two points.
The solution to this system is where both lines intersect:




RELATED QUESTIONS

I need to know how to graph x+2y=3 3x-y=-5 And I also need to know how many... (answered by longjonsilver)
I need to know how to graph 3x+y=-4 6x+2y=-8 And I also need to know how many... (answered by longjonsilver)
I need to know how to graph 3x-2y=6 x+y=2 and i also need to know how many... (answered by longjonsilver)
I need to know how to graph x+y=4 x+y=9 and i also need to know how many solutions... (answered by longjonsilver)
I need help to show me how to work out the use the substitution to solve the equations... (answered by stanbon,Earlsdon)
i need to graph and find the vertice for {{{2x-5y>4 5x+y>10 7x-4y<41}}} i don't... (answered by solver91311)
Graph the system below and write its solution. {4x+2y=6 {y=-2x+3 *It's either no... (answered by Fombitz)
Graph the system below and write its solution. {4x+2y=6 {y=-2x+3 *It's either no... (answered by Fombitz)
Could you please help me with some problems on solving system graphically? I don't... (answered by stanbon)