SOLUTION: If a rock is dropped from a building 576 feet high, then is distance in feet from the ground after "t" seconds is defined by the following equation:
f(t)=16t^2+576
how long d
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Question 527731: If a rock is dropped from a building 576 feet high, then is distance in feet from the ground after "t" seconds is defined by the following equation:
f(t)=16t^2+576
how long does it take in seconds for the rock to hit the ground? It hits the ground when f(t)=0
thank you very much
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
f(t)=-16t^2+576
set f(t) to zero and solve for t:
0=-16t^2+576
-576=-16t^2
36 = t^2
6 seconds = t
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