SOLUTION: there were 429 people nat a play. admission was $1 for adults and $.75 for children. the receits were $372.50. How many adults and how many children attended the play?
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Question 5028: there were 429 people nat a play. admission was $1 for adults and $.75 for children. the receits were $372.50. How many adults and how many children attended the play?
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let A = # of adults.
Let C = # of children.
A + C = 429 Rewrite as: C = 429-A and substitute into the equation below:
($1.00)A + ($0.75)C = $372.50
($1.00)A + ($0.75)((429-A) = $372.50 Simplify and solve for A
($1.00)A + $321.75-$0.75A = $372.50 Subtract $321.75 from both sides.
$1.00A - $0.75A = $50.75
$0.25A = $50.75 Divide both sides by $0.25
A = 203 There were 203 adults in attendance.
C = 429-A
C = 429-203
C = 226 There were 226 children in attendance.
Check:
203($1.00) + 226($0.75) = $203.00 + $169.50 = $372.50
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