# SOLUTION: Find the slope-intercept form, standard form and point slope form of the equation of the line described A line with y-intercept of (0, -3) and x-intercept of (-5, 0)

Algebra ->  Algebra  -> Systems-of-equations -> SOLUTION: Find the slope-intercept form, standard form and point slope form of the equation of the line described A line with y-intercept of (0, -3) and x-intercept of (-5, 0)      Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Algebra: Systems of equations that are not linear Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Systems-of-equations Question 480091: Find the slope-intercept form, standard form and point slope form of the equation of the line described A line with y-intercept of (0, -3) and x-intercept of (-5, 0)Answer by Alan3354(31538)   (Show Source): You can put this solution on YOUR website!Find the slope-intercept form, standard form and point slope form of the equation of the line described A line with y-intercept of (0, -3) and x-intercept of (-5, 0) ------------------ If the y-int is (0,A) and the x-int is (B,0), the eqn is Ax + By + AB = 0 ------------ -3x - 5y + 15 = 0 3x + 5y = 15 standard form ---------- y = (-3/5)x + 3 slope-intercept form -------------------------------- You can do it like this, too Find the slope, m = diffy/diffx = 3/-5 = -3/5 Use y = mx + b and either point to find b (we'll pretend we don't know it) -3 = (-3/5)*0 + b b = -3 --> y = (-3/5)x - 3 slope-int form 3x + 5y = 15