SOLUTION: solve by the substitution method. x^2+y^2=13 2x-3y=0

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Question 479127: solve by the substitution method.
x^2+y^2=13
2x-3y=0
Answer by Tatiana_Stebko(1326) About Me  (Show Source):
You can put this solution on YOUR website!
system%28x%5E2%2By%5E2=13%2C2x-3y=0%29
from the second equation -3y=-2x, or y=2x%2F3
Substitute y=2x%2F3 into the first equation
x%5E2%2B%282x%2F3%29%5E2=13
x%5E2%2B4x%5E2%2F9=13
13x%5E2%2F9=13 multiply by 9
13x%5E2=117 divide by 13
x%5E2=9
x%5B1%5D=3, x%5B2%5D=-3
substitute into y=2x%2F3
y%5B1%5D=2%2A3%2F3=2, y%5B2%5D=2%2A%28-3%29%2F3=-2
Answer (3,2) and (-3,-2)