SOLUTION: Solve the system of equations using any method. n + d + q = 28 5n +10d +25q = 495 n - d + 0 = 5

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Question 473611: Solve the system of equations using any method.
n + d + q = 28
5n +10d +25q = 495
n - d + 0 = 5

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
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Systems-of-equations/473610 (2011-07-24 00:31:13): Solve the system of equations using any method.
n + d + q = 27
5n +10d +25q = 300 divide by 5
n - 3d + 0q = 0
-----------------
n + d + q = 27 Eqn 1
n +2d + 5q = 60 Eqn 2
n -3d + 0q = 0 Eqn 3
--------------
n + d + q = 27 Eqn 1
n +2d + 5q = 60 Eqn 2
---------------------Subtract
-d - 4q = -33 Eqn A
---------
n +2d + 5q = 60 Eqn 2
n -3d + 0q = 0 Eqn 3
--------------------- Subtract
5d + 5q = 60
d + q = 12 Eqn B
-d - 4q = -33 Eqn A
------------------- Add
-3q = -21
q = 7
------
d + q = 12 Eqn B
d = 5
--------
n -3d + 0q = 0 Eqn 3
n = 15

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