SOLUTION: The total number of reds and blues was one greater than the number of greens. The sum of three times the number of reds and twice the number of blues exceeded the number of greens

Question 473392: The total number of reds and blues was one greater than the number of greens. The sum of three times the number of reds and twice the number of blues exceeded the number of greens by nine. How many of each color were there if three times the number of blues exceeded the number of greens by two?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The total number of reds and blues was one greater than the number of greens.
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The sum of three times the number of reds and twice the number of blues exceeded the number of greens by nine.
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How many of each color were there if three times the number of blues exceeded the number of greens by two?
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Equations:
r + b = g + 1
3r + 2b = g +9
3b = g + 2
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Rearrange:
r + b - g = 1
3r +2b - g = 9
0r + 3b - g = 2
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Solve by any method you know to get:
r = 3
b = 2
g = 4
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Cheers,
Stan H.

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