SOLUTION: 1. What is the determinant of the matrix [-1 2][1 3]. The [1 3] is directly under the [-1 2] in the problem. I have no idea where to begin to solve this problem.
2. The below ta
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-> SOLUTION: 1. What is the determinant of the matrix [-1 2][1 3]. The [1 3] is directly under the [-1 2] in the problem. I have no idea where to begin to solve this problem.
2. The below ta
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Question 46992This question is from textbook CLEP Official Study Guide
: 1. What is the determinant of the matrix [-1 2][1 3]. The [1 3] is directly under the [-1 2] in the problem. I have no idea where to begin to solve this problem.
2. The below table gives some of the values of a 5th degree polynominal p(x). Based on the values shown, what it the minimum number of real roots fot the equation p(x)=0
x 0 1 2 3 4 5 6 7
p(x) -30 22 110 150 34 -130 222 2,350
I have no idea how to begin to solve this problem. This question is from textbook CLEP Official Study Guide
You can put this solution on YOUR website! 1. What is the determinant of the matrix [-1 2][1 3]. The [1 3] is directly under the [-1 2] in the problem. I have no idea where to begin to solve this problem.
|-1,2|=(-1)(3)-(2)(1)=-3-2=-5
| 1,3|
IN GENERAL
|A,B|
|C,D|=A*D-B*C
2. The below table gives some of the values of a 5th degree polynominal p(x). Based on the values shown, what it the minimum number of real roots fot the equation p(x)=0
x 0 1 2 3 4 5 6 7
p(x) -30 22 110 150 34 -130 222 2,350
I have no idea how to begin to solve this problem.
REAL ROOTS ARE THOSE VALUES OF X AT WHICH P(X) BECOMES ZERO.
WE FIND THAT AT
X=0.....P(X)=-30..AND
AT X=1...P(X)=+22.....SO P(X) WOULD BE ZERO BETWEN X=0 AND X=1..THIS IS ONE REAL ROOT
SIMILARLY...AT
X=4.....P(X)=34
AT X=5....P(X)=-130.....SO P(X) WOULD BE ZERO BETWEEN X=4 AND X=5...THI9S IS ANOTHER REAL ROOT
SIMILARLY...AT X=5.....P(X)=-130
AT X=6............P(X)=222..HENCE P(X)WOULD BE ZERO BETWEEN X=5 AND X=6...THIS IS ANOTHER REAL ROOT.
HENCE THERE ARE 3 REAL ROOTS IN ALL
