SOLUTION: During the 1998-1999 Little League season, the Tigers played 52 games. They won 12 more games than they lost. How many games did they win that season? I figured if you divided 5

Question 447133: During the 1998-1999 Little League season, the Tigers played 52 games. They won 12 more games than they lost. How many games did they win that season?
I figured if you divided 52 by 2 and you get 26 then add 12 then you get the answer of 38 but not sure how to put it into an equation . Or am I even close ?
Found 2 solutions by ankor@dixie-net.com, chriswen:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
During the 1998-1999 Little League season, the Tigers played 52 games.
They won 12 more games than they lost.
How many games did they win that season?
:
Here's how they probably want you to do this:
:
Let x = no. of games won
then since the total no. of game is 52, we know:
(52-x) = no. of games lost
:
Write an equation for:
"They won 12 more games than they lost."
or
Games won = Games lost + 12 games
x = (52-x) + 12
Add x to both sides
x + x = 52 + 12
2x = 64
divide both sides by 2
x =
x = 32 games won
Answer by chriswen(106) (Show Source): You can put this solution on YOUR website!
Let x be the number of games they won.
Let x-12 be the number of games they lost.
...
x+x-12=52
2x-12=52
2x=52+12
2x=64
x=32
Therefore, the Tigers won 32 games that season.
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