SOLUTION: Please help me solve this parabola using the vertex, please explain how to find the y-intercept. Thank you y = 2x^2 + 4X -3

Question 434140: Please help me solve this parabola using the vertex, please explain how to find the y-intercept. Thank you
y = 2x^2 + 4X -3
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
You can find the zeroes, the values of x that make y = 0

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=40 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 0.58113883008419, -2.58113883008419. Here's your graph:

-----------
x = -1 - sqrt(10)/2
x = -1 + sqrt(10)/2
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For the y-intercept, let x = 0
--> (0,-3)
The vertex is (-1,-5)

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