SOLUTION: A chemist has one solution that is 25 percent acid and a second that is 50 percent acid. How many liters of each should be mixed to get 10 L of a solution that is 40 percent acid?

Question 432534: A chemist has one solution that is 25 percent acid and a second that is 50 percent acid. How many liters of each should be mixed to get 10 L of a solution that is 40 percent acid?
Found 2 solutions by josmiceli, rwm:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = liters of 25% acid to be used
Let = liters of 50% acid to be used
In words:
( acid in solution)/(total solution) = 40%
given:
= acid in 25% solution
= acid in 50% solution

----------------
(1)
(2)
From (1):
(1)
(1)
Multiply both sides of (2) by
and subtract (2) from (1)
(1)
(2)

and
(2)

4 liters of 25% acid must be used
6 liters of 50% acid must be used
check:
(1)
(1)
(1)
(1)
(1)
Answer by rwm(914) (Show Source): You can put this solution on YOUR website!
x+y=10 liters
.25x+.5y=.4*10
x=4 liters y=6 liters
naturally you need more of 50/50 solution.
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