SOLUTION: need help with this problem. x-y= 3(1) 3x-3z= 15(2) 3y+z= 6(3)

Question 425647: need help with this problem.
x-y= 3(1)
3x-3z= 15(2)
3y+z= 6(3)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x-y= 3
3x-3z= 15
3y+z= 6
----
Solve for "x" in 2nd equation:
x = z+5
Solve for "y" in 3rd equation:
y = (-z/3) + 2
----
Substitute into the 1st equation and solve for "z"
(z+5)-[(-z/3)+2] = 3
(4/3)z +5 - 2 = 3
(4/3)z = 0
z = 0
---
Solve for x and for "y":
x = z+5
x = 5
----
y = (-z/3)+2
y = 2
=================
Cheers,
Stan H.
============
---

RELATED QUESTIONS
I need help with system of equations with 3 variables. 1. Solve x + y = z -2x � 4y + z (answered by Alan3354)

Please help me solve this linear equation problem: 3x- 6y+ 3z=-3 x + 3y - z =0 6x - y (answered by Fombitz)

Linear Systems 2x+3y-z=1 x-y-z=2... (answered by AnlytcPhil)

2x-3y+4z=1 x+3y-2z=4 3x-y+z=2 So far i have tried this.. 2x-3y+4z=-1 x+3y-2x=4... (answered by Fombitz,earmstrong620)

1) x+y=9 x+2y=13 x= y= 2) 3x+7y= 24 9x+5y=24 x= y= 3) 4x+y=17 2x+3y+21 x= (answered by Fombitz)

2x-3y+z=2 x-5y+5z=3 3x+y=3z=5 This is a matrices problem I am having difficutl... (answered by stanbon)

I have a substitution problem that I would like help with, please (I have a test... (answered by Alan3354)

I need to solve the following system of linear equations with three variables. Here is... (answered by ptaylor)

x+y=z then x+y-z=0 2(x+y)=2(z) 3(x+y)=3(z) 2x+2y=2z 3x+3y=3z 2x+2y-2z=0 (answered by ichudov)