SOLUTION: Expectations As this is a fundamental "hands on" course, it is expected that you master these basic calulation and problem solving exercises. Then it is expected that you demons

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Question 412115: Expectations
As this is a fundamental "hands on" course, it is expected that you master these basic calulation and problem solving exercises.
Then it is expected that you demonstrate how these topics apply to the real world / healthcare setting.
Systems of Equations
1. Solve the following problems for X and Y in these two system equations, and for X and Y and Z, in these three system equations.
2. Fill the table, but MAKE SURE you show all your work step by step, below the table, so you may get partial credit even if your final answer is wrong.
3. Fill table 1 (worth 75%):
Table 1
Q #
Equation 1
Equation 2
Equation 3
X=
Y=
Z=

1
X+Y=9
X+2Y=13
none


none

2
3X+7Y=24
9X+5Y=24
none


none

3
4X+Y=17
2X+3Y=21
none


none

4
18X+Y=42
6X-3Y=-6
none


none

5
X+Y+2Z=5
X+Y=5
X+3Y+Z=11




6
X+10Y+Z=52
5X+Y+4Z=15
X+2y-3Z=12




7
2X+2Y+4Z=10
3X+3Y=15
4X+12Y+4Z=44




4. What is the difference between system #5 and system #7?
5. Solve Table 2 (Click here for Table 2) - Answer the question in the box (worth 25%) by:
(a) Just by looking at it, and
(b) transforming the pictures to math equations.
For example the first row would look like this:
11 = 1 Cat + 3 Waves = C+3W
Answer:
Cat =
Wave =
Heart =
U =

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi, Sry, can't help with the tables referenced...however:
Solving the following systems by elimination:
X+Y=9
X+2Y=13
-X-Y= -9 |multiplying 1st Eq thru by -1, adding to eliminate X
X+2Y=13
Y = 4 and X = 5
3X+7Y=24
9X+5Y=24
-9X-21Y=-72 |multiplying 1st Eq thru by -3, adding to eliminate X
9X+5Y = 24
-16Y =-48
Y = 3 and X = 1
4X+Y=17
2X+3Y=21
4X+Y=17
-4X-6Y=-42 |multiplying 2nd Eq thru by -2, adding to eliminate X
-5Y = -25
Y = 5 X = 3 (4X = 12 from 1st Eq)
18X+Y=42
6X-3Y=-6
18X +Y=42
-18X+9Y=18 |multiplying 2nd Eq thru by -3, adding to eliminate X
10Y = 60
Y = 6 and X = 2 (18X = 36 from 1st Eq)

X+Y=5
X+Y+2Z=5 Z = 0 |as X + Y = 5
X+3Y+Z=11
X +Y = 5
-X -3Y = -11 |multiplying 3rd Eq thru by -1, adding to 1st Eq to eliminate X
-2Y = -6
Y = 3 and X = 2
7) with the same solution as #5 |Eqs are multiples of one another
6) X = 2 Y = 5 Z = 0
Wishing You ALL the best!

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