SOLUTION: My question is...solve for x, y, z. 2x+5y+z=22 3x-3y-z=-22 5x+y+2z=-3 I have... 2x+5y+z=22 -4x-10y-2z=44 45x+18y=0 3x-3y-z=-22 5x+ y+ 2z=-3 10x-18y=-4

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Question 406673: My question is...solve for x, y, z.
2x+5y+z=22
3x-3y-z=-22
5x+y+2z=-3
I have...
2x+5y+z=22 -4x-10y-2z=44 45x+18y=0
3x-3y-z=-22 5x+ y+ 2z=-3 10x-18y=-41
___________ ____________ __________
5x+2y =0 5x-9y =41
I keep coming up with a fractionfor the last step.
Found 3 solutions by Alan3354, MathLover1, ewatrrr:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
2x+5y+z=22
3x-3y-z=-22
5x+y+2z=-3
---------------
x = -2
y = 5
z = 1
Sometimes the answers are fractions. Not this time, tho.
================
I have...
-4x-10y-2z=44 45x+18y=0
5x+ y+ 2z=-3 10x-18y=-41
---------------
1x -9y = 41 *******************

Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!
.................1.........solve for and substitute in 2
..................2
..................3


.................1


..................2


................solve for and substitute in 3




substitute in





..................3 ..substitute and

..................3...calculate







now find and










so, your answer is:



check:
.................1.





Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi

2x+5y+z=22

3x-3y-z=-22

5x+y+2z=-3



Solving by elimination 

2x+5y+z=22

3x-3y-z=-22

 5x + 2y = 0



6x-6y+2z=-44

5x+y+2z=-3

  11x - 5y = -47



 5x + 2y = 0

11x - 5y = -47



 25x + 10y = 0

 22x - 10y = -94

   47x = -94

     x = -2  and y = 5    ( 5x + 2y = 0, y = -5x/2= 10/2)

AND  z = 22-2x-5y = 1 

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