SOLUTION: Can you help me solve this system? x^2+y^2=4 and y=x^2-2

Question 387221: Can you help me solve this system? x^2+y^2=4 and y=x^2-2
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
and .
The 2nd equation becomes . Substitute.
, or .
(y+2)(y - 1) = 0.
y = -2, y = 1. When y = -2, then , so x = 0.
When y = 1, then , or , or x = , . Therefore there are 3 solutions: (, 1), (, 1), and (0, -2). The solutions correspond to the 3 points of intersection of the parabola and the circle .
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