SOLUTION: 3x-4y=8 y= 3/4x-2 I got 3x-4{3/4x-2}=8 3x-3x=16 I have no varible left? Is that right?

Algebra.Com
Question 36432: 3x-4y=8
y= 3/4x-2
I got
3x-4{3/4x-2}=8
3x-3x=16
I have no varible left? Is that right?

Found 2 solutions by checkley71, Earlsdon:
Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
ARE YOU SURE YOU COPIED THE PROBLEM CORRECTLY.
COULD IT BE Y=(3/4X)-2??????

Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
You are right in saying that you have no variable left, but finish up the problem then you can interpret the result.


No variable but the equation is valid (8 = 8).
This means that all values of x and y that satisfy the one equation will also satisfy the second equation...why?
Well, this is easier to see if you get both equations into the slope-intercept form:
1) Subtract 3x from both sides.
Divide both sides by -4.
1)
2)
You can see immediately that the two equations represent the same line so any point that lies on the first line will also lie on the second line.

RELATED QUESTIONS

Differentiate: y = x^3 - 2x^2 / cubic root x^2 What I have done: y = x^3 - 2x^2... (answered by Edwin McCravy)
4/3 ( 4x-2) - 2(3x+4) 3 x 4 ( 4x-2) - 2(3x+4) --- 3 4( 4x-2) -... (answered by askmemath)
okay this question is on our study guide for chapter 8. Find the product.... (answered by scott8148)
How would I solve these systems? 1)x+5y=4 3x-7y=-10 2)-5x+3y=6 x-y=4 (answered by elima)
Can you please tell me if i got these correct? Im doing a practice test to study for my... (answered by Edwin McCravy,solver91311)
I did this equation but I do not think it is right. Can you check it and if it is wrong... (answered by bucky)
2/3x+8>12 What i did was: 2/3x+8-8>12-8 = 2/3x>4 2/3-2/3x > 4/1*3/2 = x>6 this is... (answered by actuary)
I have three problems that I am having trouble solving I hope that is okay. Here they are (answered by stanbon)
Please help with this problem solving by substitution: 3x + 4y = 8 4.5x + 6y = 12... (answered by stanbon)