# SOLUTION: I am not sure how to solve this problem when there is a x^3 x^3 + y = 0 x^2 - y + 0

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 Algebra: Systems of equations that are not linear Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Systems-of-equations Question 34394This question is from textbook College Algebra Essentials : I am not sure how to solve this problem when there is a x^3 x^3 + y = 0 x^2 - y + 0This question is from textbook College Algebra Essentials Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!x~3+y=0 x~2-y=0 adding these two equations we get x~3+x~2=0 (the +y & the -y cancel out) now we factor x~2 out & we have x~2(x+1)=0 x~2=0 or x=0 and x+1=0 or x=-1 substituting -1 for x in both equations we get (-1)~3+y=0 or -1+y=0 or -1=-y or y=1 (-1)~2-1=0 or 1-y=0 or 1=y therefore x=-1 & y=1