SOLUTION: Find the standard form of the equation of the line passing through (5, - ⅔) and perpendicular to the graph of x = 3y.

Algebra ->  Systems-of-equations -> SOLUTION: Find the standard form of the equation of the line passing through (5, - ⅔) and perpendicular to the graph of x = 3y.       Log On


   

Question 323999: Find the standard form of the equation of the line passing through (5, - ⅔)
and perpendicular to the graph of x = 3y.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x+=+3y
y=%281%2F3%29x
The slope of this line is m=1%2F3
Perpendicular lines have slopes that are negative reciprocals.
m1%2Am2=-1
m2=-1%2Fm1=-3
Use the slope-intercept form of a line y=mx%2Bb
y=-3x%2Bb
Use the point (5,-2/3) to solve for b.
-2%2F3=-3%285%29%2Bb
b=-2%2F3%2B45%2F3
b=43%2F3
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y=-3x%2B43%2F3
3y=-9x%2B43
highlight%289x%2B3y=43%29
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