SOLUTION: solve: 1/x-4/y-3/z=19 5/x+3/y-4/z=-7 3/x+1/y+3/z=-18 the second one is : write the partial fraction decomposition of an improper rational expression ex: x^2+8

Question 318583: solve:
1/x-4/y-3/z=19
5/x+3/y-4/z=-7
3/x+1/y+3/z=-18

the second one is : write the partial fraction decomposition of an improper rational expression
ex:
x^2+8x/x^2+x-5
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
[A]=
[x]=
[b]=
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.
[A][x]=[b]
[A]inv[A][x]=[A]inv[b]
[x]=[A]inv[b]
.
.
.
det[A]=133
.
.
.
[A]inv=
[x]=
So then

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.

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.

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Check your denominator.
It does not factor simply.

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