SOLUTION: Please explain to me the steps in this equation. I am so lost and really would like to be able to do equations like this. Credit goes to http://www.wtamu.edu/academic/anns/mps/math

Question 314398: Please explain to me the steps in this equation. I am so lost and really would like to be able to do equations like this. Credit goes to http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut7_factor.htm#pst

9x^2-30xy+25y=
3x^2(3x)(5y)+(5y)^2=
(3x-5y)^2

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
9x^2-30xy+25y=
---
Not factorable the way you have posted it.
------------------------------------------------
3x^2(3x)(5y)+(5y)^2=
Common Factor: 5y
---
= (5y)(9x^3+5y)
----------------------------
(3x-5y)^2
= (3x-5y)(3x-5y)
---
Use FOIL:
F: 9x^2
O:-15xy
I:-15xy
L:25y^2
---------------
Combine to get:
9x^2 - 30xy + 25y^2
========================
Cheers,
Stan H.
========================

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