# SOLUTION: x pounds of candy valued at \$3.50 Per pounds is mixed with y pounds of candy valued at \$4.30 per pound to produce 10 pounds of a mixture selling for \$4 per pound. Fin x and y, the

Algebra ->  Algebra  -> Systems-of-equations -> SOLUTION: x pounds of candy valued at \$3.50 Per pounds is mixed with y pounds of candy valued at \$4.30 per pound to produce 10 pounds of a mixture selling for \$4 per pound. Fin x and y, the       Log On

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 Question 311617: x pounds of candy valued at \$3.50 Per pounds is mixed with y pounds of candy valued at \$4.30 per pound to produce 10 pounds of a mixture selling for \$4 per pound. Fin x and y, the number of pounds of each typeAnswer by mananth(12270)   (Show Source): You can put this solution on YOUR website!quantity equation x+y=10 cost equation 3.5x+4.3y = 10*4 multiply by 10 35x+43y=400 .. x+y=10 35x+43y=400 . multiply the first equation by 35 and subtract the second 35x+35y-35x-43y=350-400 -8y=-50 y=6.25 pounds So x= 3.75 pounds