SOLUTION: find the equation for the line tangent in y=mx+b form. f(x)=sqrt (x)/5 at (4,2/5)

SOLUTION: find the equation for the line tangent in y=mx+b form. f(x)=sqrt (x)/5 at (4,2/5)

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Question 303783: find the equation for the line tangent in y=mx+b form. f(x)=sqrt (x)/5 at (4,2/5)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!

y' =
y' =
At x = 4, y = 2/5, y' = 1/20 = m
---------------
2/5 = (1/20)*4 + b
b = 1/5
--> y = (1/20)x + 1/5

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