SOLUTION: 15x+11y=132, 2x+3y=59

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Question 29715: 15x+11y=132, 2x+3y=59
Answer by Cintchr(475) About Me  (Show Source):
You can put this solution on YOUR website!
+15x+%2B+11y+=+132+
++2x+%2B++3y+=++59+
to solve, we can solve for x in the 2nd equation and plug it into the first to find y.
++2x+%2B++3y+=++59+ subtract 3y from both sides
++2x+=+59+-3y+ divide all parts by 2
++2x%2F2+=+59%2F2+-3y%2F2+
++x+=+59%2F2+-3y%2F2+ plug this back into equation #1
+15x+%2B+11y+=+132+
+15%2859%2F2+-3y%2F2%29+%2B+11y+=+132+ distribute 15 to the quantity
+885%2F2+-45y%2F2%29+%2B+11y+=+132+ change the fractions to a common denom of 2
+885%2F2+-45y%2F2+%2B+11y%282%29%2F%282%29+=+132%282%29%2F%282%29+ drop the denoms
+885+-45y+%2B+11y%282%29+=+132%282%29+ multiply
+885+-45y+%2B+22y+=+264+ combine like terms
+885+-+23y+=+264+ subtract 885 from both sides
+-23y+=+264+-+885+
+-23y+=+-621+ divide by -23
+y+=+27+
pick either of the equations and plug y=27 in.
++2x+%2B++3y+=++59+
++2x+%2B++3%2827%29+=++59+ multiply
++2x+%2B++81+=++59+ subtract 81 from both sides
++2x++=++-22+ divide both sides by 2
x+=+-11+
the solution, or ordered pair, where the two lines cross is :
(-11,27)