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put this solution on YOUR website!The larger of two numbers is 4 less than 3 times the smaller number. If 3 more than twice the larger number is decreased by twice the smaller number, the result is 11. Find the numbers.
Let x be the smaller number and y the larger number. Then we have:
1.) y = 3x - 4
2.) (2y + 3) - 2x = 11
Substitute 3x-4 for y from equation 1.) in equation 2.) and solve for x. Then calculate y = 3x-4