SOLUTION: SOLVE BY ELIMINATION METHOD 5R-4S=-17 4R+5S=52

Question 263070: SOLVE BY ELIMINATION METHOD
5R-4S=-17
4R+5S=52
Answer by dabanfield(803) (Show Source): You can put this solution on YOUR website!
1.) 5R-4S=-17
2.) 4R+5S=52
We need to multiply both sides of each of the equations by values that will produce a common coefficient on either x or y in both equations so that when the equations are either added together or subtracted one of the variables is eliminated:
We can eliminate R by multiplying the first equation by 4 and the second equation by 5:
4*5R - 4*4S = 4*-17
5*4R + 5*5S = 5*52
Simplifying these we have:
3.) 20R - 16S = -68
4.) 20R + 25S = 260
Subtracting equation 4.) from 3.) we then have:
-41S = -328
S = 8
Substitute 8 for S in either of the original two equations and calculate R.

RELATED QUESTIONS
Can someone help me solve by the elimination method. 5r � 4s =2 4r +5s = 18 What is... (answered by MathLover1)

Solve by elimination method 3r-4s=-19... (answered by checkley77)

5r-4s= -6 and... (answered by oberobic)

3r-5s=21 5r+3s=33 solve by elimination... (answered by stanbon)

solve by elimination method 5r=9s=-26... (answered by Alan3354)

Solve by elimination method 2r - 5s = -14 5r + 2s = 52 what is the solution of the... (answered by Maths68)

Solve by the elimination method. 7r - 4s =24 4r + 7s =88 (answered by Alan3354)

Solve by the elimination method. 3r-4s=14... (answered by ankor@dixie-net.com)

5r-3s=17 3r+5s=51 Elimination... (answered by stanbon,mananth)