SOLUTION: Solve by substitution y^2=1+2x^2 x^2+2y^2=22 my options are (3,2),(3,-2), (-2,3), (-2,-3) (2,3), (2,-3), (-2,3), (-2,-3) (radical 7, radical 15) (-radical 7, radical 15) (ra

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Question 254911: Solve by substitution
y^2=1+2x^2
x^2+2y^2=22
my options are
(3,2),(3,-2), (-2,3), (-2,-3)
(2,3), (2,-3), (-2,3), (-2,-3)
(radical 7, radical 15) (-radical 7, radical 15) (radical 7,-radical 15) (- radical 7, -radical 15)
(radical 15, radical 7) (radical 15, -radical 7)(-radical 15,radical 7, (-radical 15,-radical 7)
I am not getting any of these answers

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Start with the second equation.


Plug in


Distribute


Subtract 22 from both sides.


Combine like terms.


Notice that the quadratic is in the form of where , , and


Let's use the quadratic formula to solve for "x":


Start with the quadratic formula


Plug in , , and


Square to get .


Multiply to get


Rewrite as


Add to to get


Multiply and to get .


Take the square root of to get .


or Break up the expression.


or Combine like terms.


or Simplify.


So the solutions for 'x' are or


Now take each solution for 'x' and plug them into to find the corresponding 'y' solutions.


Let's find the corresponding solutions for y when


Start with the first equation.


Plug in (the first 'x' solution)


Square 2 to get 4.


Multiply


Add


Take the square root of both sides (don't forget the plus/minus)


or Break up the plus/minus


or Take the square root of 9 to get 3.


So when , we have two solutions for 'y' which are or . So we have two ordered pairs (2,3) and (2,-3)

--------------------------------------------------

Now let's find the corresponding solutions for y when


Start with the first equation.


Plug in (the second 'x' solution)


Square 2 to get 4.


Multiply


Add


Take the square root of both sides (don't forget the plus/minus)


or Break up the plus/minus


or Take the square root of 9 to get 3.


So when , we have two solutions for 'y' which are or . So we have two more ordered pairs (-2,3) and (-2,-3)

==================================================================

Answer:


So the four ordered pair solutions are (2,3), (2,-3), (-2,3), and (-2,-3) which means that the answer is B)

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