SOLUTION: How do you factor the following system of equations?
3x-y=-2
x^3-y=0
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Question 253592: How do you factor the following system of equations?
3x-y=-2
x^3-y=0
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
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Solve each for y and then set them equal to each other
3x-y=-2
3x+2=y
x^3-y=0
x^3=y
x^3=3x+2
x^3-3x-2=0
Now we factor
(x-2)(x+1)^2 = 0
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