SOLUTION: mary has $3.75 in nickels, dimes, and quarters. She has three more quarters than dimes. She has twice as many nickels as quarters. How many of each coin does she have?

Question 252314: mary has $3.75 in nickels, dimes, and quarters. She has three more quarters than dimes. She has twice as many nickels as quarters. How many of each coin does she have?
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
This requires a few equations. First Let N = nickel, D = dime, and Q = quarter. From the first sentence, we get

This equation is the "value" equation. Notice also I don't use decimal points. Easier to get rid of them I think. Next,
"Three more quarters than dimes".
"Twice as many nickels as quarters}}}
Put all of this together using only Q, we get
5(2Q) + 10(Q-3) + 25Q = 375
Solving for Q, you get Q = 9.
Find the others, N = 18 and D = 6. So we have 18 nickels, 6 dimes, and 9 quarters.
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