SOLUTION: I wrote the problem incorrectly for the nonlinear system by substitution. x^2+y^2=25 x^2-y=5

Question 250425: I wrote the problem incorrectly for the nonlinear system by substitution.
x^2+y^2=25
x^2-y=5
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I wrote the problem incorrectly for the nonlinear system by substitution.
x^2+y^2=25
x^2-y=5
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Solve for x^2:
x^2 = y+5
---------------------
Substitute for x^2 and solve for "y":
y+5 + y^2 = 25
y^2 + y - 20 = 0
(y+5)(y-4) = 0
y = -5 or y = 4
--------------------
Find the corresponding values of "x":
If y = -5,
x^2 = -5+5
x^2 = 0
x = 0
(0,-5)
---------
If y = 4
x^2 = 4+5
x = 3 or -3
(3,4)(-3,4)
---------------------
The parabola intersects the circle at three points: (3,4),(-3,4),(0,-5)
---------------------
Cheers,
Stan H.

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