You can
put this solution on YOUR website!Let

= liters of 20% juice needed
Let

= liters of 10% juice needed
given:
(1)

liters of 12% mixture
OJ in 20% juice is

liters
OJ in 10% juice is

liters
OJ in 12% juice is

liters
In words:
(liters OJ in 20% mix + liters OJ in 10% mix)/(total liters of 12% mix) = 12%

(2)

Subtract (1) from (2)
(2)

(1)

liters
and, since

liters
2 liters of the 20% juice and 8 liters of the 10%
juice need to be mixed
check answer:

OK