SOLUTION: Solve the System.
2x+3y+2z=1
2x-3y+2z=-1
4x+3y-2z=4
x=
y=
z=
Algebra.Com
Question 186542: Solve the System.
2x+3y+2z=1
2x-3y+2z=-1
4x+3y-2z=4
x=
y=
z=
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
2x + 3y + 2z = 1
2x - 3y + 2z =-1
4x + 3y - 2z = 4
:
Use elimination with subtraction on 1st two equations
2x + 3y + 2z = 1
2x - 3y + 2z =-1
------------------
0x + 6y + 0z = 2
6y = 2
y = =
:
Add the last two equations, eliminate y & z, find x
2x - 3y + 2z =-1
4x + 3y - 2z = 4
------------------
6x + 0y + 0z = 3
6x = 3
x = =
:
Using the 1st equation, substitute for x & y, to find z
2() + 3() + 2z = 1
1 + 1 + 2z = 1
2z = 1 - 2
z =
;
;
You can check the solutions in the 2nd and 3rd equation
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