SOLUTION: Solve the system.
2x+2y+3z=10
3x+y-z=0
x+y+2z=6
x=
y=
z=
Algebra.Com
Question 186539: Solve the system.
2x+2y+3z=10
3x+y-z=0
x+y+2z=6
x=
y=
z=
Answer by uday1435(57) (Show Source): You can put this solution on YOUR website!
2x+2y+3z=10 (1)
3x+y-z=0 (2)
x+y+2z=6 (3)
Multiply eqn (2) by 2 and subtract from eqn(1)
2x+2y+3z=10 (1)
6x+2y - 2z=0 (2) x 2
- 4x + 5z = 10 (4) (1) – (2) x 2
Multiply eqn (3) by 2 and subtract from eqn(1)
2x+2y+3z=10 (1)
2x+2y+4z=12 (5) (3) x 2
- z = - 2
So z = 2
Plugging in the value of z in eqn(4)
- 4x + 5(2) = 10; -4x = 10-10 =0; so x = 0
Now plug-in the values of x (=0) ad z (=2) in eqn (3)
x + y + 2z = 6 (3)
0 + y +2(2) =6
y + 4 =6; so y = 6-4 = 2
So the answers are x =0, y=2, z = 2
If you need further clarification, please email: udayakumar.t.r@gmail.com
RELATED QUESTIONS
solve the system
x+y+z=-1
x-y+3z=-17
2x+y+z=-2
Solve the system
x-y+2z=7... (answered by solver91311)
Solve the system:
x - y + 3z = 23/2
3x + 2y + 2z = -6
2x - z =... (answered by ronak_hahs)
1.Solve the system of equations.
x-2y+3z=7
2x+y+z=4... (answered by MathLover1,MathTherapy)
Solve the following system.
2x + 4y + 3z = 2
x + 2y - z = 0
4x + y - z = 6
(answered by ikleyn)
Solve the following system of linear eqnations.
x + y – 3z + 2w = 0
2x - y + 2z (answered by Fombitz)
Solve the system:
{{{3x-y+2z=3}}}
{{{2x+3y-z=-3}}}
{{{x-2y+3z=2}}}
Thanks... (answered by swincher4391)
solve the following homogeneous system of linear equations:
x+y-3y+2w=0,
2x-y+2z-3w=0,
(answered by Alan3354)
2x + 3z = 4
3y + 2z = 5
3x + 4y = −16
(x, y, z) =
2x +... (answered by Alan3354)
3x+y+2z=80 x+2y-z=10 2x-y+3z=70
solve... (answered by stanbon)