SOLUTION: Ramon mixes 12 liters of 8% acid solution with a 20% acid solution, which results in a 60% acid solution. Find the number of liters of 20% acid solution in the new mixture.

Question 176631: Ramon mixes 12 liters of 8% acid solution with a 20% acid solution, which results in a 60% acid solution. Find the number of liters of 20% acid solution in the new mixture.
Found 2 solutions by solver91311, Mathtut:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The stated result is impossible. The mixture solution must be a smaller concentration than at least one of the constituents. Now if you meant "...12 liters of 80% acid..." you would have a solvable problem. Write back with the correct problem statement.
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
I am going to assume that is suppose to be 16 % and not 60% since that isnt possible. It has to fall between 8% and 20% solutions for this to work. You cannot mix two percentage mixtures together and get less than the lowest or greater than the highest amounts. lets call the amount of 20% solution x.
:
.08(12)+.2(x)=.16(12+x)
:
.96+.2x=1.92+.16x
:
.04x=.96
:
liters of 20% solution
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