SOLUTION: please help me solve these problems! Thanks! x^3-3x2-x+3=0 y^2+2y-21=-2y

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Question 167537: please help me solve these problems! Thanks!
x^3-3x2-x+3=0
y^2+2y-21=-2y

Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!



Factor just the first two terms:
          
         factor out  
         

Factor just the last two terms
         (((-x+3}}}  
         factor out 
         

Substitute  for the
first two terms and 
for the last two terms in





Now factor the whole parentheses 
out of both:



The binomial in the second parentheses is the 
difference or two squares, as you see:



So it factors as :



Use the zero-factor principle:


 
---------------------------



Get  on the right by adding  to both sides of:





Think of two whole numbers which when multiplied gives 
and when added gives .  They are 
and .  So the left side factors as



Use the zero-factor principle:

  

Edwin

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