SOLUTION: x-y+z x+y+3z 2x-y+2z The correct answer is suppose to be (4,2,-3). However the answer I keep getting is (-3,1/2, 1 1/2). Can you please help me.

SOLUTION: x-y+z x+y+3z 2x-y+2z The correct answer is suppose to be (4,2,-3). However the answer I keep getting is (-3,1/2, 1 1/2). Can you please help me.

Algebra.Com

Question 165025This question is from textbook
: x-y+z
x+y+3z
2x-y+2z
The correct answer is suppose to be (4,2,-3). However the answer I keep getting is (-3,1/2, 1 1/2). Can you please help me. This question is from textbook

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
x-y+z
x+y+3z
2x-y+2z
----------
There's a piece missing. No equal signs.
RELATED QUESTIONS
Please help... I tried to solve this, but no result. I eliminated z in 1&2,and 2&3, but... (answered by htmentor,ikleyn)

i have tried this problem four times and i keep getting the same ordered triple (2,-5,3). (answered by stanbon,scott8148)

Hello! I'm having problems with substitution and for the following problem i keep getting (answered by stanbon)

-2x+3y+z=3 3x-y+2z=2 x+2y-3z=1 the answer they provided us is 13/21,25/21,2/3 i do not (answered by Edwin McCravy,emargo19)

Can I get help with Solving Systems please? Solve The System 5(x+1)-(y+3)=-6... (answered by rfer)

I've been multiplying polynomials however, the solution that I come up with for the... (answered by solver91311)

2) Solve the following linear system using matrices: 2x-y+3z=-4... (answered by Fombitz)

I am having a hard time finishing this problem. I need to find the equation of the... (answered by Alan3354)

Solve. If the system's equations are dependent or it there is no solution, state this. (answered by Alan3354)