SOLUTION: Given: x h(x) 1 2 2 3 3 6 4 11 5 18 What I have figured out: Square x and then subtract progressive odd numbers and the answer is h(x). Examples: 1 s

Question 16117: Given:
x h(x)
1 2
2 3
3 6
4 11
5 18
What I have figured out: Square x and then subtract progressive odd numbers and the answer is h(x).
Examples:
1 squared = 1
subtract -1 = 2
2 squared = 4
subtract 1 = 3
3 squared = 9
subtract 3 = 6
4 squared = 16
subtract 5 = 11
5 squared = 25
subtract 7 = 18
I dont' know how to write the equation.
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
there are 2 patterns here:

1. the squaring of the "counter" 1,2,3,4,5, etc
2. the -1,1,3,5,7, pattern which is basically a x2 table (2,4,6,8,10) just "shifted.

OK then:
1. if the counter is n, then we have n^2.
2. x2 table is 2n, but ours is shifted, so that first number (should be 2) is now -1.... ie 2n-3

So combine them, we have

Check...at random, let n=5 (answer should be 18)

We have 5^2 - 2*5 + 3
--> 25 - 10 + 3
--> 15 + 3
--> 18

jon.

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