SOLUTION: how do i solve this problem {{{y=2x^2-7x+3}}} {{{x-3=y}}}

Question 159983: how do i solve this problem

Found 2 solutions by stanbon, checkley77:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how do i solve this problem

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Since they are both equal to "y", set them equal to each other to get:
2x^2 -7x + 3 = x - 3
2x^2 - 8x = 0
2x(x-4) = 0
x = 0 or x = 4
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Cheers,
Stan H.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!

2x^2-7x+3=x-3
2x^2-7x-x+3+3=0
2x^2-8x+6=0
2(x^2-4x+3)=0
2(x-3)(x-1)=0
x-3=0
x=3 answer.
x-1=1
x=1 answer.
y=3-3=0 answer.
y=1-3=-2 answer.
(3,0) & (1,-2)

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