SOLUTION: solve using addition method: 3x^2-2y^2=-5 2x^2-y^2=-2
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Algebra: Systems of equations that are not linear
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Question 152809
:
solve using addition method:
3x^2-2y^2=-5
2x^2-y^2=-2
Answer by
checkley77(12569)
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3x^2-2y^2=-5
2x^2-y^2=-2 multiply this equation by -2 & add.
-4x^2+2y^2=4
3x^2-2y^2=-5
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x^2+0=-1
x^2+1=0
x=0+/-1i (this has complex roots)