SOLUTION: solve the system using your choice of method: x^2-y^2-4x+6y-4=0 x^2+y^2-4x-6y+12=0

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Question 152174: solve the system using your choice of method:
x^2-y^2-4x+6y-4=0
x^2+y^2-4x-6y+12=0

Answer by kev82(151)   (Show Source): You can put this solution on YOUR website!
Adding the equations together looks like it may be a good place to start, where exactly are you stuck? Can you show some working?
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I added them and came up with 2x^2-8x+8=0, this is where I was stuck

This is a quadratic equation. If you are given a problem like the one above, you should really be quite comfortable with this type of equation already, and the techniques of how to solve it. You have no idea?
I don't really like the site solver, but try and follow this. However I suggest you go and see your teacher and cover solving quadratics.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=128 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 4.82842712474619, -0.82842712474619. Here's your graph:


When you have solved for the possible values of x, you must then find y. Substituting for x should leave you some more quadratic equations to solve to give y, you can use the same technique again.

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