# SOLUTION: The owner of cool beans coffee shop mixes french roast coffee worth \$9.00 per with Kenyan coffee worth \$7.50 per pound in order to get 10 pounds of a mixture worth \$8.40 per pound.

Algebra ->  Algebra  -> Systems-of-equations -> SOLUTION: The owner of cool beans coffee shop mixes french roast coffee worth \$9.00 per with Kenyan coffee worth \$7.50 per pound in order to get 10 pounds of a mixture worth \$8.40 per pound.      Log On

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 Question 145097: The owner of cool beans coffee shop mixes french roast coffee worth \$9.00 per with Kenyan coffee worth \$7.50 per pound in order to get 10 pounds of a mixture worth \$8.40 per pound. How much of each type of coffee was used? number of pounds of french roast coffee_______ number of poundsof Kenyan coffee_____Answer by josmiceli(9654)   (Show Source): You can put this solution on YOUR website!Let = pounds of french roast used Let = pounds of Kenyan used Substitute this value of into the other equation The owner used pounds of French roast and pounds of Kenyan coffee