SOLUTION: Solve by addition. If a unique solution does not exist, state whether the system is inconsistent or dependent.
1. 5x + 4y = 7
5x – 2y = 19
2. 3x – 4y = 2
4x – y =
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Question 127387: Solve by addition. If a unique solution does not exist, state whether the system is inconsistent or dependent.
1. 5x + 4y = 7
5x – 2y = 19
2. 3x – 4y = 2
4x – y = 20
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
# 1
Start with the given system of equations:
Now in order to solve this system by using elimination/addition, we need to solve (or isolate) one variable. I'm going to solve for y.
In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for , we would have to eliminate (or vice versa).
So lets eliminate . In order to do that, we need to have both coefficients that are equal in magnitude but have opposite signs (for instance 2 and -2 are equal in magnitude but have opposite signs). This way they will add to zero. By adding to zero, they can be eliminated.
So to make the coefficients equal in magnitude but opposite in sign, we need to multiply both coefficients by some number to get them to an common number. So if we wanted to get and to some equal number, we could try to get them to the LCM.
Since the LCM of and is , we need to multiply both sides of the top equation by and multiply both sides of the bottom equation by like this:
Multiply the top equation (both sides) by
Multiply the bottom equation (both sides) by
Distribute and multiply
Now add the equations together. In order to add 2 equations, group like terms and combine them
Combine like terms and simplify
Notice how the x terms cancel out
Simplify
Divide both sides by to isolate y
Reduce
Now plug this answer into the top equation to solve for x
Start with the first equation
Plug in
Multiply
Add 8 to both sides
Combine like terms on the right side
Divide both sides by 5 to isolate x
Divide
So our answer is
and
which also looks like )
Now let's graph the two equations (if you need help with graphing, check out this solver)
From the graph, we can see that the two equations intersect at . This visually verifies our answer.
graph of (red) and (green) and the intersection of the lines (blue circle).
# 2
Start with the given system of equations:
Now in order to solve this system by using elimination/addition, we need to solve (or isolate) one variable. I'm going to solve for y.
In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for , we would have to eliminate (or vice versa).
So lets eliminate . In order to do that, we need to have both coefficients that are equal in magnitude but have opposite signs (for instance 2 and -2 are equal in magnitude but have opposite signs). This way they will add to zero. By adding to zero, they can be eliminated.
So to make the coefficients equal in magnitude but opposite in sign, we need to multiply both coefficients by some number to get them to an common number. So if we wanted to get and to some equal number, we could try to get them to the LCM.
Since the LCM of and is , we need to multiply both sides of the top equation by and multiply both sides of the bottom equation by like this:
Multiply the top equation (both sides) by
Multiply the bottom equation (both sides) by
Distribute and multiply
Now add the equations together. In order to add 2 equations, group like terms and combine them
Combine like terms and simplify
Notice how the x terms cancel out
Simplify
Divide both sides by to isolate y
Reduce
Now plug this answer into the top equation to solve for x
Start with the first equation
Plug in
Multiply
Add 16 to both sides
Combine like terms on the right side
Divide both sides by 3 to isolate x
Divide
So our answer is
and
which also looks like )
Now let's graph the two equations (if you need help with graphing, check out this solver)
From the graph, we can see that the two equations intersect at . This visually verifies our answer.
graph of (red) and (green) and the intersection of the lines (blue circle).
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