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Solve the given system of equations. / Los die gegwe stelsel van vergelykings op. (12)
4x + y + 3z = 1
8x + 9z = 10
- 6x + 3y + 12z = - 4
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4x + y + 3z = 1 (1)
8x + 9z = 10 (2)
-6x + 3y + 12z = -4 (3)
Multiply equation (1) by 2
8x + 2y + 6z = 2.
Replace here 8x by (10 - 9z), based on equation (2). You will get
(10-9z) + 2y + 6z = 2,
or
2y -3z = -8. (4)
Multiply equation (3) by 4
-24x + 12y + 48z = -16.
Replace here -24x by -3*(10 - 9z), based on equation (2). You will get
-3*(10-9z) + 12y + 48z = -16,
or
12y + 75z = 14. (5)
So, you reduced the original system (1),(2),(3) to two equations (4) and (5)
2y - 3z = -8. (4)
12y + 75z = 14. (5)
Nultiply equation (4) by 6; keep equation (5) as is
12y - 18z = -48. (4)
12y + 75z = 14. (5)
Subtract equation (4) from equation(5). The terms with "12y" will casncel each other, and you will get
93z = 62, giving z = 62/93 = 2/3.
Substituting z= 2/3 into equation (5), you get
12y + 50 = 14, giving 12y = -36, y = -36/12 = -3.
Substituting z= 2/3 into equation (2), you get
8x + 6 = 10, giving 8x = 4, x = 4/8 = 1/2.
ANSWER. x= 1/2, y= -3, z= 2/3.
CHECK. I checked this solution by substituting the found values into original equations and got confirmation.
Solved.