SOLUTION: {4x^2-y^2=-5 {8x^2+y^2=17

Question 1187572: {4x^2-y^2=-5
{8x^2+y^2=17

Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
We appreciate the info.
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.

Add the equations.

As soon as you add them, the terms {-y^2} and {y^2} will cancel each other.

You will get simple quadratic equation for x.

Solve it and get two answers/values for x.

Then substitute these values to any of the original equations.

You will get a simple quadratic equation for y: it will give you two solutions for y.

Combine these solutions in pairs; be accurate with the signs of the values in pairs.

You should have 4 pairs (if there is no degeneracy).

They determine 4 solutions/answers.

This 4 solutions represent the intersection points of two curves, determined by the equations.

You may report me about your progress . . .

RELATED QUESTIONS
4x^2-y^2=-5 8x^2+y^2=17 (answered by Alan3354)
4x^2-y^2=-5 8x^2+y^2=17 (answered by Alan3354)
Solve the system: { 4x^2 - y^2 = -5 { 8x^2 + y^2 =... (answered by Alan3354)
4x62-y^2=-5 8x^2+y^2=17 (answered by Alan3354)
Y=-x^2-8x-17 (answered by greenestamps,josgarithmetic,ikleyn)
4x^2-y^2+8x+2y=13 (answered by josgarithmetic)
5(y+2)=... (answered by Abbey)
Find the x-intercept... (answered by dabanfield)
1. y>x^2-8x+17= (answered by Alan3354)